(0)
Let C be a directed n-cycle
,
and v and w two vertices
outside of C with edges
and
those
.
We call such a graph
a double-wheel. Note that the edges
and
are non-flippable
without making directed 3-cycles, while the edges
are flippable.
(1)
Let B be a directed cycle of size 4.
Let us add 2 double-wheels whose directed cycles
C1 and C2, respectively, are size 4 as
Figure 1.
Then the resulting graph H(1) has all the edges
non-flippable except the eight edges in the two directed
cycles C1 and C2.
Note that the graph H(1) has no directed 3-cycles.
(2)
As same as step (1), we add a pair of double-wheels to
each flippable cycle as Figure 2.
The resulting graph H(2) has all the edges
non-flippable except 16 edges in 4 directed cycles.
Let us call the center cycle B and 4 flippable
cycles C1, C2, C3 and C4.
The graph H(2) still has no directed 3-cycles.
(3)
Let
H(2)1,
H(2)2,
H(2)3and
H(2)4 be 4 copies of H(2)of step (2). Let us denote the center cycle of Hi by Bi.
Now identify the flippable cycles Cj of 4 graphs
H(2)i,
for each j.
The resulting graph H(3) has 4 flippable
cycles Cj (
)
and 4 non-flippable
cycles Bk (
), where the cycles
Cj, Bk are mutually disjoint.
Other edges are all non-flippable.
Observe that this identification does not make no directed
3-cycles.
(4)
Let
H(3)1,
H(3)2,
H(3)3
and
H(3)4 be n ()
copies of H(3) of
step (3), and each graph
H(3)k have 4 flippable
cycles
Ci(H(3)k) (
)
and
non-flippable cycle
Bi(H(3)k) which are
mutually disjoint.
Now identify the cycle Ci(H(3)k) with Bi(H(3)k+1) for each fixed pair (i, j, k), where the summation is taken in modulo n. The resulting graph G has no directed 3-cycles and no flippable edges.